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Q. A parabola $ y^2 = 32x $ is drawn. From its focus, a line of slope $ 1 $ is drawn. The equation of the line is

J & K CETJ & K CET 2018

Solution:

The given parabola is $y^2 = 32 \,x \,\,...(i)$
Focus $= (8, 0)$; Slope $= 1$
$\Rightarrow $ Equation of line passing through $(8, 0)$ and
having slope $1$ is $y - 0 = 1(x - 8)$
$\Rightarrow y = x - 8$