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Q. A paper, with two marks having separation $d$, is held normal to the line of sight of an observer at distance of $50\, m$. The diameter of the eye lens of the observer is $2\, mm$. Light wavelength $5000\,\mathring{A}$ is made to fall on the lens. The least value of $d$, so that the marks can be seen as separate, will be :

AFMCAFMC 2002

Solution:

Resolving power is the ability of lens to measure the angular separation of images that are close together.
The resolving power of a lens is limited by diffraction effects. The lens aperture is a hole that is analogous to a two dimensional version of the single slit experiment.
For an ideal lens the resolution is
$d =\frac{1.22 \lambda \times D}{a}$
$d =\frac{1.22 \times 5000 \times 10^{-10} \times 50}{2 \times 10^{-3}}$
$=1.525\, cm$