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Q. A $p-n$ junction diode when forward biased has a potential drop of $0.3\, V$ which is assumed to be independent of current. The current more than $15\, mA$ through the diode produces a large heating effect which damages the diode. If we want to use a $5\, V$ battery to forward bias the diode, the value of the resistor used in series with the diode so that the maximum current does not exceed $12\, mA$ is________ $\Omega$.

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$V=5-0.3=4.7\, V$
$\therefore R =\frac{ V }{ I } =\frac{4.7}{12 \times 10^{-3}}$
$=0.39167 \times 10^{3}$
$=391.67 \Omega$