1. Tardigrade
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  3. Physics
  4. A oil drop having a mass 4.8 × 10-10 g and charge 2.4 × 10-18 C stands still between two charged horizontal plates separated by a distance of 1 cm. If now the polarity of the plates is changed, instantaneous acceleration of the drop is: (g=10 ms -2)

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Q. A oil drop having a mass $4.8 \times 10^{-10} \,g$ and charge $2.4 \times 10^{-18} \,C $ stands still between two charged horizontal plates separated by a distance of $1 \,cm$. If now the polarity of the plates is changed, instantaneous acceleration of the drop is : $\left(g=10 \,ms ^{-2}\right)$

EAMCETEAMCET 2006

Solution:

$a=\frac{F}{m}=\frac{q E}{m}=\frac{m g}{m}$
$g=10 \,m / s ^{2}$