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  4. A nucleus with mass number 220 initially at rest emits an α particle. If the Q value of the reaction is 5.5 MeV, the kinetic energy of the α particle is

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Q. A nucleus with mass number $220$ initially at rest emits an $\alpha$ particle. If the $Q$ value of the reaction is $5.5 \,MeV$, the kinetic energy of the $\alpha$ particle is

Nuclei

Solution:

$K_{\alpha}=\frac{\left(A-4\right)}{A} Q$
Here, $A = 220, Q=5.5\,MeV$
$K_{\alpha}=\left(\frac{220-4}{220}\right)5.5\,MeV$
$=\left(\frac{216}{220}\right)5.5\,MeV$
$=5.4\,MeV$