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  4. A nucleus of mass M at rest splits into two parts having masses ( M prime/3) and (2 M prime/3)( M prime< M ). The ratio of de Broglie wavelength of two parts will be :

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Q. A nucleus of mass $M$ at rest splits into two parts having masses $\frac{ M ^{\prime}}{3}$ and $\frac{2 M ^{\prime}}{3}\left( M ^{\prime}< M \right)$. The ratio of de Broglie wavelength of two parts will be :

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Solution:

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$\left|\vec{ P }_1\right|=\left|\vec{ P }_2\right|$
Here $\vec{P}$ is momentum
So $\lambda=\frac{ h }{ P }$
Hence both will have same de broglie wavelength.