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  4. A n-p-n transistor is connected to common emitter configuration in a given amplifier. A load resistance of 800 is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Ω, the voltage gain and the power gain of the amplifier will respectively be

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Q. A $n-p-n$ transistor is connected to common emitter configuration in a given amplifier. A load resistance of $800$ is connected in the collector circuit and the voltage drop across it is $0.8\, V$. If the current amplification factor is $0.96$ and the input resistance of the circuit is $192\,\Omega$, the voltage gain and the power gain of the amplifier will respectively be

NEETNEET 2016Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Given $\alpha = 0.96$
so, $\beta = \frac{\alpha}{1- \alpha} = \frac{0.96}{0.04} \, \Rightarrow \, \beta = 24$
Voltage gain for common emitter configuration
$A_V = \beta . \frac{R_L}{R_1} = 24 \times \frac{800}{192} = 100$
Power gain for common emitter configuration
$P_V = \beta A_V = 24 \times 100 = 2400 $
Voltage gain for common base configuration
$A_V = \alpha . \frac{R_L}{R_P} = 0.96 \times \frac{800}{192} = 4 $
Power gain for common base configuration
$P_V = A_V \alpha = 4 \times 0.96 = 3.84 $
* In the question it is asked about common emitter configuration but we got above answer for common base configuration.