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  4. A normal human eye can see an object making an angle of 1.8° at the eye. What is the approximate height of object which can be seen by an eye placed at a distance of 1 m from the object? <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/470bd617964a9f838b2c2f2476342ada-.png />

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Q. A normal human eye can see an object making an angle of $1.8^{\circ}$ at the eye. What is the approximate height of object which can be seen by an eye placed at a distance of $1 m$ from the object?
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Physical World, Units and Measurements

Solution:

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$\frac{h}{1}=\theta$
$\frac{ h }{1}=1.8 \times \frac{\pi}{180} m$
$h=\frac{1.8 \times \pi \times 100}{180}$
$h=\pi \,cm$