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Q. A non-zero vector $\vec{a}$ is such that its projections along vectors $\frac{\hat{i}+\hat{j}}{\sqrt{2}}, \frac{-\hat{i}+\hat{j}}{\sqrt{2}}$ and $\hat{k}$ are equal, then unit vector along $\vec{a}$ is

Vector Algebra

Solution:

Let the projection be $x$, then
$\vec{a}=\frac{x(\hat{i}+\hat{j})}{\sqrt{2}}+\frac{x(-\hat{i}+\hat{j})}{\sqrt{2}}+x \hat{k}$
$\therefore \vec{a}=\frac{2 x \hat{j}}{\sqrt{2}}+x \hat{k} $ or $ \hat{a}=\frac{\sqrt{2}}{\sqrt{3}} \hat{j}+\frac{\hat{k}}{\sqrt{3}}$