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Q. A non-conducting solid sphere of radius R is uniformly charged. The magnitude of the electric field due to the sphere at a distance r from its centre (1) increases as r increases for r < R (2) decreases as r increases for $ 0
BHUBHU 2011

Solution:

Inside the sphere $ E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{{{R}^{3}}}r $ $ E\propto r $ for $ r\le R $ i.e., E at centre = 0 as $ r=0 $ and E at surface
$=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{{{R}^{2}}} $ as $ r=R $
Outside the sphere $ E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{{{r}^{2}}} $ for $ r\ge R $ or $ E\propto \frac{1}{{{r}^{2}}} $
Thus, variation of electric field (E) with distance (r) from the centre will be shown

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