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Q. A network of twelve resistances each of resistance $R$ form a square of squares as shown in the figure. The outer square is fitted in a metal ring of negligible resistance. Find the resistance between centre of the square and the ring
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Current Electricity

Solution:

$1 ,2 ,3 ,4$ are at same potential; $5 ,6 ,7 ,8$ are at same potential
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$R_{eq} = \frac{R}{4} + \frac{R}{8} = \frac{3R}{8}$