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Q. A network of six identical capacitors, each of value $C$, is made as shown in the figure. The equivalent capacitance between the points $A$ and $B$ isPhysics Question Image

Electrostatic Potential and Capacitance

Solution:

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$\frac{1}{2 C}+\frac{1}{C}=\frac{1}{C^{\prime}} \text { or } C'=\frac{2 C}{3}$
$C'$ and $C'$ are in parallel. Hence, the equivalent capacitance between $A$ and $B$ is
$C_{ eq }=2 \times \frac{2 C}{3}=\frac{4}{3} C$