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Q.
$A\frac{NaNO_{2} / HCl}{0 ^\circ C}$ Benzyl alcohol $+N_{2}\uparrow$ The molecular formula of $A$ is $C_{x}H_{y}N.$ The value of $y$ is_____.
NTA AbhyasNTA Abhyas 2022
Solution:
Compound $'A'$ on reacting with nitrous acid at $0^\circ C$ gives benzyl alcohol and nitrogen gas which indicates that, the compound $'A'$ is benzylamine (primary aliphatic amine).
Benzyal alcohol
(A)
The molecular formula of $(A)$ is $C _7 H _9 N$.
$
\therefore y=9
$