1. Tardigrade
  2. Question
  3. Chemistry
  4. A motor vehicle radiator was filled with 8 litre of water in which 2 litre of methyl alcohol was added. What is the lowest temperature at which the vehicle can be parked out without a danger of freezing of water? (Kf for water = 1.86 K kg mol-1 and density of methanol = 0.8 g/mL)

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Q. A motor vehicle radiator was filled with 8 litre of water in which 2 litre of methyl alcohol was added. What is the lowest temperature at which the vehicle can be parked out without a danger of freezing of water? ($K_f$ for water $= 1.86\, K\, kg\, mol^{-1}$ and density of methanol $= 0.8 \,g/mL$)

Solutions

Solution:

$ΔT_{f} = K_{f } \frac{W_{B}\times1000}{M_{B} \times W_{A}}$
Weight of alcohol $\left(W_{B}\right) = 2000 × 0.8$
Weight of water $\left(W_{A}\right) = 8000 × 1$
$ΔT_{f} = \frac{1.86×2000×0.8×1000}{32×8000} = 11.625$
Freezing point of solution $= 0 - 11.625 = -11.625^{\circ}C$
So, vehicle cannot be kept out below $-11.625^{\circ}C.$