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Q. A monoatomic anion of unit charge contains 45 neutrons and 36 electrons. Identify the ion.

JIPMERJIPMER 2015Structure of Atom

Solution:

Let the monoatomic anion be $X^-$.Number of electrons in $X- = 36$
$\therefore $ Number of electrons in monoatomic atom $(X)$
$= 36 - 1 = 35 $
Atomic number = number of electrons in neutral atom = number of protons in neutral atom $ = 35$
Mass number of monoatomic atom $(X)$ = number of protons + number of neutrons
$= 35 + 45 = 80$ Hence, ion must be $Br^-$.