Q. A monkey of mass $40\, kg$ climbs up a rope, of breaking load $600\, N$ hanging from a ceiling. If it climbs up the rope with the maximum possible acceleration, then the time taken by monkey to climb up is [Length of rope is $10\, m ]$
Laws of Motion
Solution:
$600-400 =40 a$
$a =\frac{200}{40}=5\, m / s ^{2}$
$S =u t+\frac{1}{2} a t^{2}$
$10 =\frac{1}{2}(5) t^{2}$
$\Rightarrow t =2$ second
