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Q. A monkey of mass $20\, kg$ is holding a vertical rope. The rope will not break when a mass of $25\, kg$ is suspended from it but will break if the mass exceeds $25\, kg.$ What is the maximum acceleration with which the monkey can climb up along the rope ? $(g = 10\, m/s^2)$

AIPMTAIPMT 2003Laws of Motion

Solution:

Let $T$ be the tension in the rope when monkey climbs up with an acceleration $a$. Then,
$T-m g=m a$
$25 g-20 g=20 a $
$\Rightarrow a=\frac{5 \times 10}{20}=2.5 \,m / s ^{2} $