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  4. A, mixture x containing 0.02 mol of [Co(NH3)5SO4]Br and 0.02 mol of [Co(NH3)5Br]SO4 was prepared in 2 L of solution. 1 L of mixture X + excess AgNO+3 → Y 1 L of mixture X + excess BaCl2 → Z The number of moles of Y and Z are

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Q. A, mixture $x$ containing $0.02$ mol of $[Co(NH_3)_5SO_4]Br$ and $0.02$ mol of $[Co(NH_3)_5Br]SO_4$ was prepared in $2\,L$ of solution.
$1\, L$ of mixture $ X +$ excess $AgNO+3 \to Y$
$1 \,L$ of mixture $X +$ excess $BaCl_2 \to Z$
The number of moles of $Y$ and $Z$ are

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Solution:

A mixture $X$ containing $0.02$ mol of $[Co(NH_3)_5SO_4]Br$ and $0.02$ mol of $[CO(NH_3)_5Br]SO_4$ was prepared in $2\, L$ of solution. This means $1 \,L$ of the mixture contains $0.01$ mol of $[Co(NH_3)_5SO_4]Br$ $0.01$ mol of $[Co(NH_3)_5Br]SO_4$.
$1 \,L$ of mixture $X +$ excess $AgNO_3 \to 0.01$ mol $AgBr$
$1 \,L$ of mixture $X +$ excess $BaCl_2 \to 0.01$ mol $BaSO_4$
This is according to the following reactions taking place:
$[Co(NH_3)_5SO_4]Br + AgNO_3\to [Co(NH_3)_5SO_4]NO_3 + AgBr \downarrow$
$[Co(NH_3)_5Br]SO_4 + BaCl_2 \to [Co(NH_3)_5Br]Cl_2 + BaSO_4 \downarrow$