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  4. A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is: [Use atomic masses (in g mol-1) :N = 14,Ar = 40]

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Q. A mixture of $N_2$ and $Ar$ gases in a cylinder contains $7\,g$ of $N_2$ and $8\,g$ of $Ar$. If the total pressure of the mixture of the gases in the cylinder is $27\, bar$, the partial pressure of $N_2$ is :
[Use atomic masses (in g $mol^{-1}$) :$N = 14,Ar = 40$]

NEETNEET 2020States of Matter

Solution:

Partial presure of $N_2 =$ mole fraction $\times P_{Total}$ of $N_2$
$X_{N_2} = \frac{\text{moles of }N_2}{\text{ total moles}}$
moles of $N_2 = \frac{7}{28} = \frac{1}{4};$
moles of $Ar = \frac{8}{40} = \frac{1}{5}$
$X_{N_2} = \frac{(\frac{1}{4})}{\frac{1}{4} + \frac{1}{5}} = \frac{5}{9}$
$P_{N_2} = \frac{5}{9} \times 27 = 15 $ bar