Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A mixture of $2$ moles of helium gas (atomic mass $=4 amu$ ) and 1 mole of argon gas (atomic mass $=40$ $amu$ ) is kept at $300 K$ in a container. The ratio of the rms speeds $\left(\frac{ v _{ mm }(\text { helium })}{ v _{ rma }(\text { argon })}\right)$ is

JEE AdvancedJEE Advanced 2012

Solution:

$v _{ rms }=\sqrt{\frac{3 RT }{ M }}$
Required ratio $=\sqrt{\frac{ M _{ A e}}{ M _{ He }}}$
$=\sqrt{\frac{40}{4}}=\sqrt{10}$
$=3.16 .$