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  4. A mixture contains N2O4 and NO2 in 2: 1 ratio by volume. The vapour density of the mixture is

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Q. A mixture contains $N_{2}O_{4}$ and $NO_{2}$ in 2 : 1 ratio by volume. The vapour density of the mixture is

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Solution:

Vapour density of mixture $=\frac{n_{1} d_{1} + n_{2} d_{2}}{n_{1} + n_{2}}$

Here molecular weight of $NO_{2}$ = 46

Molecular weight of $N_{2}O_{4}=92$

Density $=\frac{m o l e c u l a r \,w e i g h t}{2}$

$=\frac{2 \times 46 + 1 \times 23}{2 + 1}=38.3$