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  4. A mixture consists of two radioactive materials A1 and A2 with half lives of 20 s and 10 s respectively. Initially the mixture has 40 g of A1 and 160 g of A2 The amount of the two in the mixture will become equal after

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Q. A mixture consists of two radioactive materials $ A_1$ and $A_2$ with half lives of $20\,s$ and $10\, s$ respectively. Initially the mixture has $40 \,g$ of $A_1$ and $160 \,g$ of $A_2$ The amount of the two in the mixture will become equal after

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Solution:

For $A,\, 40\, g \stackrel{20 s }{\longrightarrow } 20 g \stackrel{20 s }{\longrightarrow } 10 g$
For $B,\, 160\, g \stackrel{10 s }{\longrightarrow } 80 g \stackrel{10 s }{\longrightarrow } 40 g \stackrel{10 s }{\longrightarrow } 20 g \stackrel{10 s }{\longrightarrow } 10 g$