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  3. Chemistry
  4. A mixed solution of potassium hydroxide and sodium carbonate required 15 mL of an N / 20 HCl solution when titrated with phenolphthalein as an indicator. But the same amount of the solution when titrated with methyl orange as indicator required 25 mL of the same acid. the amount of KOH present in the solution is

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Q. A mixed solution of potassium hydroxide and sodium carbonate required $15 \,mL$ of an $N / 20\, HCl$ solution when titrated with phenolphthalein as an indicator. But the same amount of the solution when titrated with methyl orange as indicator required $25 \,mL$ of the same acid. the amount of $KOH$ present in the solution is

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Solution:

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i. $(x \times 1)+(y \times 2) \times \frac{1}{2}=\frac{1}{20} \times 15$
ii. $(x \times 1)+(y \times 2)=\frac{1}{20} \times 25$
$ \Rightarrow y=0.5$ and $x=$ $0.25$
$\Rightarrow KOH =x$ mmoles $=0.25 \times 10^{-3} \times 56\, g =$ $0.014\, g$