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Q. A milliammeter of range $10\, mA$ has a coil of resistance $1 \,\Omega$. To use it as an ammeter of range $1 \,A$, the required shunt must have a resistance of

Current Electricity

Solution:

$S=\frac{i_{g} G}{\left(I-i_{g}\right)}=\frac{0.01 \times 1}{1-0.01}=\frac{1}{99} \Omega$