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Physics
A milliammeter of range 10 mA has a coil of resistance 1 Ω. To use it as an ammeter of range 1 A, the required shunt must have a resistance of
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Q. A milliammeter of range $10\, mA$ has a coil of resistance $1 \,\Omega$. To use it as an ammeter of range $1 \,A$, the required shunt must have a resistance of
Current Electricity
A
$\frac{1}{101} \Omega$
11%
B
$\frac{1}{100} \Omega$
41%
C
$\frac{1}{99} \Omega$
31%
D
$\frac{1}{9} \Omega$
17%
Solution:
$S=\frac{i_{g} G}{\left(I-i_{g}\right)}=\frac{0.01 \times 1}{1-0.01}=\frac{1}{99} \Omega$