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Q. A microscope is focused on a mark on a piece of paper and then a slab of glass of thickness $3 \,cm$ and refractive index $1.5$ is placed over the mark. How should the microscope be moved to get the mark in focus again?

Haryana PMTHaryana PMT 2008

Solution:

Apparent depth of mark as seen through a glass slab of thickness $x$ and refractive index $ \mu $ ,
is Apparent depth $ =\frac{\text{Real depth}}{\text{Refractive index}} $
or $ x=\frac{x}{\mu }=\frac{3}{1.5}=2 \,cm $
As image appears to be raised by $1 \,cm$,
therefore, microscope must be moved upward by $1 \,cm$