Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A metallic sphere of mass $ M $ falls through glycerine with a terminal velocity $ v $ . If we drop a ball of mass $ 8M $ of same metal into a column of glycerine, the terminal velocity of the ball will be

Mechanical Properties of Fluids

Solution:

$ M=\frac{4}{3} \pi r^{3} \rho $ and $ 8M =\frac{4}{3} \pi R^{3}\, \rho $ ,
$ \therefore R^{3}=8r^{3} $ or $ R=2r $
As $ v \propto r^{2} $
$ \therefore \frac{v'}{v}=\left(\frac{R}{r}\right)^{2}=\left(\frac{2r}{r}\right)^{2} $
$ =4 $ or $ v' =4v $