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Q. A metallic bar of coefficient of linear expansion $10^{-5} K^{-1}$ is heated from $0^{\circ}C$ to $100^{\circ}C$. The percentage increase in its length is

KEAMKEAM 2015Thermal Properties of Matter

Solution:

Given, $\alpha=10^{-5} K ^{-1}$
and $\Delta T=100^{\circ}-0^{\circ}=100^{\circ} C$
We know that, percentage increase in its length,
$\frac{\Delta l}{l} \times 100=\alpha \Delta T \times 100$
$\frac{\Delta l}{l}=10^{-5} \times 100=10^{-3}$
$\therefore \frac{\Delta l}{l} \times 100=0.1 \%$