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Physics
A metallic bar of coefficient of linear expansion 10-5 K-1 is heated from 0°C to 100°C. The percentage increase in its length is
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Q. A metallic bar of coefficient of linear expansion $10^{-5} K^{-1}$ is heated from $0^{\circ}C$ to $100^{\circ}C$. The percentage increase in its length is
KEAM
KEAM 2015
Thermal Properties of Matter
A
0.1 %
71%
B
1%
12%
C
10%
0%
D
0.01 %
6%
E
0.001%
6%
Solution:
Given, $\alpha=10^{-5} K ^{-1}$
and $\Delta T=100^{\circ}-0^{\circ}=100^{\circ} C$
We know that, percentage increase in its length,
$\frac{\Delta l}{l} \times 100=\alpha \Delta T \times 100$
$\frac{\Delta l}{l}=10^{-5} \times 100=10^{-3}$
$\therefore \frac{\Delta l}{l} \times 100=0.1 \%$