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  4. A metal plate of area 1 × 10-4 m2 is illuminated by a radiation of intensity 16 mW/m2. The work function of the metal is 5 eV. The energy of the incident photons is 10 eV and only 10 % of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be: [1 eV = 1.6 × 10-19 J]

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Q. A metal plate of area $1 \times 10^{-4} \; m^2$ is illuminated by a radiation of intensity $16\, mW/m^2$. The work function of the metal is $5\,eV$. The energy of the incident photons is $10\, eV$ and only $10\%$ of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be : $[1 \; eV = 1.6 \times 10^{-19} J]$

JEE MainJEE Main 2019Dual Nature of Radiation and Matter

Solution:

$I =\frac{nE}{At} $
$ 16\times10^{-3} =\left(\frac{n}{t}\right)_{\text{Photon}} \frac{10\times1.6 \times10^{-19}}{10^{-4}} =10^{12} $