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Chemistry
A metal crystallises in BCC lattice with unit cell edge length of 300 pm and density 6.15 g cm-3 . The molar mass of the metal is
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Q. A metal crystallises in $BCC$ lattice with unit cell edge length of $300\, pm$ and density $6.15\, g\, cm^{-3}$ . The molar mass of the metal is
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The Solid State
A
$50\, g\, mol ^{-1}$
B
$60\, g\, mol ^{-1}$
C
$40\, g\, mol ^{-1}$
D
$70\, g\, mol ^{-1}$
Solution:
$d =\frac{ ZM }{ a ^{3} N _{ A }}$
$6.15=\frac{2 \times M }{\left(3 \times 10^{-8}\right)^{3} \times 6.02 \times 10^{23}}$
$M =\frac{6.15 \times 27 \times 10^{-24} \times 6.02 \times 10^{23}}{2}$
$M =50\, g / mol$