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  4. A metal coin is at the bottom of a beaker filled with a liquid of refractive index 4 / 3 to height of 6 cm. To an observer looking from above the surface of the liquid, coin will appear at a depth of :

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Q. A metal coin is at the bottom of a beaker filled with a liquid of refractive index $4 / 3$ to height of $6\, cm$. To an observer looking from above the surface of the liquid, coin will appear at a depth of :

ManipalManipal 2002

Solution:

Here : Actual depth of liquid $h=6\, cm$
Refactive index of the liquid $=\frac{4}{3}$
Using the relation
$\mu=\frac{\text { actual depth }(h)}{\text { apparent depth }(x)}=$
or $x=h \times \frac{3}{4}=6 \times \frac{3}{4}=4.5\, cm$
Hence, the coin will appear at a depth of
$=6-4.5=1.5\, cm$