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  4. A metal coin is at the bottom of a beaker filled to a height of 6 cm. The refractive index of the liquid is (4/3). To an observer looking above the surface of the liquid, the coin will appear raised up by

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Q. A metal coin is at the bottom of a beaker filled to a height of $6 cm$. The refractive index of the liquid is (4/3). To an observer looking above the surface of the liquid, the coin will appear raised up by

Ray Optics and Optical Instruments

Solution:

Here, $\mu=\frac{4}{3}$, Real depth $=6 \,cm$
$\mu=\frac{\text { Real depth }}{\text { Apparent depth }}$
Apparent depth $=\frac{6}{(4 / 3)}=\frac{18}{4}=4.5\, cm$
The coin will appear to be raised $=6 \,cm -4.5 \,cm =1.5 \,cm$