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  4. A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is

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Q. A mass of $ 6 \,kg $ is suspended by a rope of length $ 2\, m $ from a ceiling. A force of $ 50 \,N $ in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is

KEAMKEAM 2007Laws of Motion

Solution:

$ \tan \theta =\frac{50}{6g}=0.83 $
or $ tan\text{ }\theta =tan\text{ }40{}^\circ $ or $ \theta =40{}^\circ $

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