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Q. A mass of 20 kg moving with a speed of 10 m/s collides with another stationary mass of 5 kg. As a result of the collision both masses stick together. The kinetic energy of the composite mass will be

Rajasthan PMTRajasthan PMT 2009Work, Energy and Power

Solution:

Given, $ {{m}_{1}}=20kg,\,\,{{\mu }_{1}}=10\,\,m/s $ $ {{m}_{2}}=5kg,\,\,{{\mu }_{2}}=0 $ Using law of conservation of momentum, $ {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=({{m}_{1}}+{{m}_{2}})v $ $ 20\times 10+5\times 0=(20+5)\times v $ $ \therefore $ $ v=\frac{200}{25}=8\,\,m/s $ Kinetic energy of the composite mass $ =\frac{1}{2}({{m}_{1}}+{{m}_{2}}){{v}^{2}} $ $ =\frac{1}{2}(20+5)\times {{(8)}^{2}}=2.5\times 32=800\,\,J $