1. Tardigrade
  2. Question
  3. Physics
  4. A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45°at the roof point. If the suspended mass is at equilibrium, the magnitude of the force (in newton) applied is (g = 10 ms-2)

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Q. A mass of $10\, kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of $45^{\circ}$at the roof point. If the suspended mass is at equilibrium, the magnitude of the force (in newton) applied is $\left(g = 10 ms^{-2}\right)$

Laws of Motion

Solution:

image
At equilibrium,
tan $45^{\circ} = \frac{mg}{F} = \frac{100}{F}$
$\therefore F = 100N$