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Q. A mass $m$ slides from rest down the surface of a frictionless hemispherical bowl of radius $r$ from the highest point $A$. The velocity of mass when it reaches the bottom isPhysics Question Image

Uttarkhand PMTUttarkhand PMT 2007

Solution:

From the condition $m g r=\frac{1}{2} m v^{2}$
$\Rightarrow 2 g r=v^{2} $
$\Rightarrow v=\sqrt{2 g r}$