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Q. A mass $m$ moving horizontally (along the $x$-axis) with velocity $v$ collides and sticks to a mass of $3m$ moving vertically upward (along the $y$ -axis) with velocity $2\,v$. The final velocity of the combination is

AIPMTAIPMT 2011Work, Energy and Power

Solution:

From the law of conservation of linear momentum
$mv \,\hat{ i }+(3 m )(2\, v ) \hat{ j } $
$=4 \,mv '$
$v'=\frac{v}{4} \hat{i}+\frac{3}{2} v\hat{j}$