Question

A mass $M$ is suspended by a rope from rigid support at $A$ as shown in the figure. Another rope is tied at the end $B$ and it is pulled horizontally with a force $F$ . If the rope $AB$ makes an angle $\theta $ with the vertical, then the tension in the string $AB$ is

• A. $Fsin \theta $
• B. $\frac{F}{s i n \theta }$
• C. $Fcos \theta $
• D. $\frac{F}{c o s \theta }$

Answer 1

Answer: (B)

$\frac{T}{sin \left(90\right)^{o}}=\frac{F}{sin ⁡ \left(\pi - \theta \right)}=\frac{M g}{sin ⁡ \left(\frac{\pi }{2} + \theta \right)}$
Or $T=\frac{F}{s i n \theta }=\frac{M g}{c o s \theta }$