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  4. A mass m falls freely from rest. The linear momentum after it has fallen through a height h is: (g = acceleration due to gravity)

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Q. A mass m falls freely from rest. The linear momentum after it has fallen through a height h is: (g = acceleration due to gravity)

EAMCETEAMCET 1998

Solution:

When the body is falling freely from height h, then from third equation of motion $ {{v}^{2}}-{{u}^{2}}=2gh $ $ (\because \,u=0) $ $ \therefore $ $ {{v}^{2}}=2gh\Rightarrow v=\sqrt{2gh} $ Now, linear momentum of body is given $ p=m\text{ }v $ From Eqs.(i) and (ii) Momentum $ =m\sqrt{2gh} $