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  4. A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coefficient of friction is

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Q. A marble block of mass $2 \,kg$ lying on ice when given a velocity of $6\, m/s$ is stopped by friction in $10\, s$. then the coefficient of friction is

AIEEEAIEEE 2003Laws of Motion

Solution:

Retardation $\frac{u}{t}=\frac{6}{10}=0.6\,m/sec^{2}$
Frictional force $= μ\, mg = ma$
$\therefore \mu=\frac{a}{g}=\frac{0.6}{10}=0.06.$