Question

A man weighs 80 kg the stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s. What would be the reading on the scale? $ 400N $

• A. $ mg\,sin\,\theta $
• B. $ \frac{{{p}^{2}}{{t}^{2}}}{m} $
• C. zero
• D. $ \frac{{{p}^{2}}{{t}^{2}}}{2m} $

Answer 1

Answer: (B)

Mass of man m = 80 kg Acceleration of lift = 5 m/s When lift is moving upwards, the reading of weighing scale will be equal to R. The equation of motion gives $ 1:5:3 $ $ {{(Kg)}^{1/2}} $ $ {{(Kg)}^{-1/2}} $ $ {{(Kg)}^{2}} $