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Physics
A man travels 4 km due East and then 3 km due North. The magnitude of his displacement is:
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Q. A man travels 4 km due East and then 3 km due North. The magnitude of his displacement is:
JIPMER
JIPMER 1999
A
7 km
B
1 km
C
5 km
D
None of these
Solution:
The magnitude of his displacement is $ =\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}=\sqrt{16+9}=5km $