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Q. A man running at a speed of $5 \, km/h$ finds that the rain is falling vertically. When he stops running, he finds that the rain is falling at an angle of $60^{o}$ with the horizontal. The velocity of rain with respect to running man is

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

$V_{r}= \, \text{velocity of rain} \\ \, \\ \text{V}_{\text{rm}}=\text{ velocity of rain with respect to man} \\ \\ \text{V}_{\text{m}}=\text{ velocity of man}$
Solution
$tan 30^{o}=\frac{V_{m}}{V_{r m}}$
$V_{r m}=\frac{5}{\frac{1}{\sqrt{3}}}=5\sqrt{3} \, km/h$