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  4. A man of weight 75 kg is standing in an elevator which is moving with an acceleration of 5 m/s2 in upward direction the apparent weight of the man will be: (g=10 m/s2)

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Q. A man of weight $ 75\,kg $ is standing in an elevator which is moving with an acceleration of $5\,m/s^{2}$ in upward direction the apparent weight of the man will be: $ (g=10\,m/s^{2})$

Punjab PMETPunjab PMET 2004Laws of Motion

Solution:

Here : Mass of the man $m=75\, kg$
Acceleration of elevator $a=5\, m / s$
The apparent weight of the man is
$W =m(g +a)=75 \times(10+5)$
$=1125\, N$