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Q. A man of mass M stands at one end of a plank of length L which lies at rest on a frictionless surface. The man walks to other end of the plank. If the mass of the plank is $\frac{ M }{3}$, then the distance that the man moves relative to ground is :

Laws of Motion

Solution:

Le the distance moved by plank is $x$
$m _{1} \Delta x _{1}+ m _{2} \Delta x _{2}=0$
$M ( L - x )+\frac{ M }{3}(- x )=0 $
$\Rightarrow x =\frac{3 L }{4}$
$\therefore $ distance moved by person w.r.t. to ground
$= L - x =\frac{ L }{4}$