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Q. A man of mass 60 kg is standing on a spring balance inside a lift. lf the lift falls freely downwards, then the reading of the spring balance will be

KEAMKEAM 2005Laws of Motion

Solution:

When lift falls freely downward, then
$ \, \, \, \, \, \, \, \, $ mg - R = ma
Here, $ \, \, \, \, \, \, $ a =g
$ \therefore \, \, \, \, \, \, \, \, $ R =0
Hence, reading of spring balance is zero.