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  3. Physics
  4. A man of mass 60 kg is standing on a horizontal conveyer belt. When the belt is given an acceleration of 1 ms -2, the man remains stationary with respect of the moving belt. If g =10 ms -2, the net force acting on the man is

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Q. A man of mass $60 kg$ is standing on a horizontal conveyer belt. When the belt is given an acceleration of $1 ms ^{-2},$ the man remains stationary with respect of the moving belt. If $g =10 ms ^{-2},$ the net force acting on the $man$ is

Laws of Motion

Solution:

$F_{ net }=m a=60 \times 1=60$