1. Tardigrade
  2. Question
  3. Physics
  4. A man of mass 60 kg is standing on a boat of mass 140 kg, which is at rest in still water. The man is initially at 20 m from the shore. He starts walking on the boat for 4 s with constant speed 1.5 m / s towards the shore. The final distance of the man from the shore is

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Q. A man of mass $60\, kg$ is standing on a boat of mass $140\, kg$, which is at rest in still water. The man is initially at $20\, m$ from the shore. He starts walking on the boat for $4\, s$ with constant speed $1.5\, m / s$ towards the shore. The final distance of the man from the shore is

System of Particles and Rotational Motion

Solution:

Distance travelled by the man on boat in 4 second $=(1.5) \times 4 = 6.0 \,m$
$140 x=60(6-x)$
$140 x=360-60 x$
$x=1.8\, m$
So final distance of the man from the shore will be
$20-(6-1.8)=15.8\, m$

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