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  4. A man moves in an open field such that after moving 10 m on a straight line, he makes a sharp turn of 60° to his left. The total displacement after 8 such turn is equal to

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Q. A man moves in an open field such that after moving $10\, m$ on a straight line, he makes a sharp turn of $60^{\circ}$ to his left. The total displacement after $8$ such turn is equal to

Motion in a Straight Line

Solution:

image
After 8 such turns object is at ' $B$ '.
Displacement $=A B$
Two vectors are at $60^{\circ}$
$\sqrt{10^{2}+10^{2}+2 \times 10^{2} \times \frac{1}{2}}$
$=10 \sqrt{3} m$
$\Rightarrow 17.32\, m = AB$