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Q. A man misses a bus by 40 minutes, if he travels at $30 kmph$. If he travels at $40 kmph$, then also he misses the bus by 10 minutes. What is the minimum speed required to catch the bus on time?

Time and Distance

Solution:

Let the distance to be travelled to catch the bus be $x km$.
$\frac{x}{30}-\frac{x}{40}=\frac{30}{60} $
$\frac{4 x-3 x}{120}=\frac{30}{60} \Rightarrow x=60 km$
By travelling $30 kmph$ time taken $=\frac{60}{30}=2$ hours
By taking 2 hours, he is late by $40 min$. So, he has to cover $60 km$ in 1 hour $20 min$ to catch the bus.
The minimum speed $=\frac{60}{\frac{4}{3}}=45 kmph$.