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Q.
A man fires a bullet of mass $20 \,g$ at a speed of $100 \,m/s$. The gun is of $2 \,kg$ mass. By what velocity the gun rebounds backward?
Laws of Motion
Solution:
Linear momentum will remain conserved
$m _{ g } v _{ g }= m _{ b } v _{ b }$
$v _{ g }=\frac{ m _{ b } v _{ b }}{ m _{ g }}$
$=\frac{20 \times 10^{-3} \times 100}{2}=1 m / s$